+ The Arrhenius Equation The Arrhenius equation shows the relationship between the rate constant k and the temperature T

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+ The Arrhenius Equation The Arrhenius equation shows the relationship between the rate constant k and the temperature T

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The Arrhenius Equation The Arrhenius Equation Shows The Relationship Between The Rate Constant K And The Temperature T 1
The Arrhenius Equation The Arrhenius Equation Shows The Relationship Between The Rate Constant K And The Temperature T 1 (48.91 KiB) Viewed 30 times
The Arrhenius Equation The Arrhenius Equation Shows The Relationship Between The Rate Constant K And The Temperature T 2
The Arrhenius Equation The Arrhenius Equation Shows The Relationship Between The Rate Constant K And The Temperature T 2 (61.39 KiB) Viewed 30 times
+ The Arrhenius Equation The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k= Ae-Ea/RT where R is the gas constant (8.314 J/mol. K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is Ea 1 m架=器(云-云) 71 which is mathmatically equivalent to Ea 袅=器 (1 - 1) 1/2 (1/22 In 1/12 = where k₁ and k2 are the rate constants for a single reaction at two different absolute temperatures (T1 and T2).
▼ The activation energy of a certain reaction is 42.0 kJ/mol. At 22 °C, the rate constant is 0.0150s ¹. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. ►View Available Hint(s) T2 = Submit Part B μA Value f Units www. ? Given that the initial rate constant is 0.0150s-¹ at an initial temperature of 22 °C, what would the rate constant be at a temperature of 200. °C for the same reaction described in Part A?
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