5-1. 5-2. 5-3. Draw Lewis structures for the following molecules and polyatomic ions, including all equivalent resonance

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5-1. 5-2. 5-3. Draw Lewis structures for the following molecules and polyatomic ions, including all equivalent resonance

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5 1 5 2 5 3 Draw Lewis Structures For The Following Molecules And Polyatomic Ions Including All Equivalent Resonance 1
5 1 5 2 5 3 Draw Lewis Structures For The Following Molecules And Polyatomic Ions Including All Equivalent Resonance 1 (208.76 KiB) Viewed 33 times
5-1. 5-2. 5-3. Draw Lewis structures for the following molecules and polyatomic ions, including all equivalent resonance structures, if appropriate. Show your calculations to find the total number of valence electrons. a. (2) ● For each of the molecules shown in the Lewis structures below: (1) List every central atom in the molecule/ion, and for each central atom, identify the following: Ideal bond angle Geometry name Type of orbitals used for the sigma bonds and nonbonding electrons Molecules: ● B₂Cl₂F₂ ● ● ● a. b. HCO3 a. C. Sketch the geometry showing approximately correct angles. Draw "sticks" with dots at the end for nonbonding electrons for the central atoms. You do not need to show nonbonding electrons for non-central atoms. :0: || :Cl-C-N-H | H CNCI b. Determine whether each of the following molecules is polar or nonpolar. Justify your answers. Do not simply list the criteria for a polar molecule. For full credit, the justification for each one must include: O=N-O-CI: d. CBr₂Cl₂ C. C. Lewis structure (including calculation of total valence electrons) Geometry sketch Calculation of JAEN| values for all bonds using electronegativities provided on the Course Resources page 0= Si = Se Statement about whether the molecule is symmetric or not, with an explanation for how you can tell (be specific) CC1₂F2 A sentence explaining how all this information connects to your answer of polar or nonpolar. Use your own words and complete sentences. Be detailed and complete. The phrase "overall dipole" should be part of your explanation. NBr3 b. SF₂ d. BBr3
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