Masses (g) Mass of Filter Paper Mass of Na₂CO3 Mass of Ca(NO3)2.4H₂O Mass of (Filter paper AND solid) Mass of solid (CaC
Posted: Thu Jul 07, 2022 1:45 pm
Results & Calculations. 1. Mass of Na2CO3 2. No. of moles of Na₂CO3 = mass / MM 3. Mass of Ca(NO3)2.4H₂O = 4. No. of moles of Ca(NO3)2.4H₂O = mass / MM = 5. Equation of the reaction: Ca(NO3)2(aq) + Na₂CO3(aq) - CaCO3(s) + 2NaNO3(aq) g g g 6. No. of moles of the product(CaCO3) if Ca(NO3)2 is the limiting reactant pl= moles 7. No. of moles of the product(CaCO3) if Na₂CO3 is the limiting reactant p2= moles 8. The limiting reactant is 9. Theoretical yield of CaCO3 = no of moles x MM=.......... 10. Mass of filter paper = 11. Mass of (filter paper and dry solid) H 12. Mass of the product (CaCO3) = g 13. Percentage yield Experimental yield Experimental yield X 100 = Theoretical yield moles g moles = g %