Masses (g) Mass of Filter Paper Mass of Na₂CO3 Mass of Ca(NO3)2.4H₂O Mass of (Filter paper AND solid) Mass of solid (CaC

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

Masses (g) Mass of Filter Paper Mass of Na₂CO3 Mass of Ca(NO3)2.4H₂O Mass of (Filter paper AND solid) Mass of solid (CaC

Post by answerhappygod »

Masses G Mass Of Filter Paper Mass Of Na Co3 Mass Of Ca No3 2 4h O Mass Of Filter Paper And Solid Mass Of Solid Cac 1
Masses G Mass Of Filter Paper Mass Of Na Co3 Mass Of Ca No3 2 4h O Mass Of Filter Paper And Solid Mass Of Solid Cac 1 (59.55 KiB) Viewed 23 times
Masses G Mass Of Filter Paper Mass Of Na Co3 Mass Of Ca No3 2 4h O Mass Of Filter Paper And Solid Mass Of Solid Cac 2
Masses G Mass Of Filter Paper Mass Of Na Co3 Mass Of Ca No3 2 4h O Mass Of Filter Paper And Solid Mass Of Solid Cac 2 (61.92 KiB) Viewed 23 times
Masses (g) Mass of Filter Paper Mass of Na₂CO3 Mass of Ca(NO3)2.4H₂O Mass of (Filter paper AND solid) Mass of solid (CaCO3) DATA Group Group 1 2 1.250 1.400 0.505 1.520 1.700 Group 3 1.220 0.500 0.515 1.550 1.530 1.850 1.680 0.450 0.455 0.460
Results & Calculations. 1. Mass of Na2CO3 2. No. of moles of Na₂CO3 = mass / MM 3. Mass of Ca(NO3)2.4H₂O = 4. No. of moles of Ca(NO3)2.4H₂O = mass / MM = 5. Equation of the reaction: Ca(NO3)2(aq) + Na₂CO3(aq) - CaCO3(s) + 2NaNO3(aq) g g g 6. No. of moles of the product(CaCO3) if Ca(NO3)2 is the limiting reactant pl= moles 7. No. of moles of the product(CaCO3) if Na₂CO3 is the limiting reactant p2= moles 8. The limiting reactant is 9. Theoretical yield of CaCO3 = no of moles x MM=.......... 10. Mass of filter paper = 11. Mass of (filter paper and dry solid) H 12. Mass of the product (CaCO3) = g 13. Percentage yield Experimental yield Experimental yield X 100 = Theoretical yield moles g moles = g %
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply