Please if needed, circle the right correct answers! Thank you!

Post by **answerhappygod** » Thu Jul 07, 2022 12:13 pm

: Please If Needed Circle The Right Correct Answers Thank You 1 (191.76 KiB) Viewed 27 times

You study color variants of Arabidopsis hypotheticus, a plant with red flowers. You have obtained three pure-breeding mutant lines, all named for their place of origin. Two lines have white flowers (Aberdeen White and Victoria White), and one has yellow flowers (Kansas Yellow). You begin your analysis by crossing each line with wild-type plants and selfing the F₁ to produce an F2 generation. fo Cross Aberdeen White X Victoria White faf X Kansas Yellow X wild type wild type wild type F₁ phenotype wild type wild type wild type F₂ phenotypes and ratios 3 wild type : 1 white 3 wild type : 1 white *) 3 wild type : 1 yellow
From these crosses you conclude that the mutations in all three lines are recessive to the wild type. Part A - Crossing lines with the same recessive phenotype You continue your analysis by crossing the Aberdeen White and Victoria White lines. This time you count the actual numbers of progeny in the two F2 phenotypic classes. F₂ phenotypes and numbers Cross Aberdeen White x Victoria White F₁ phenotype wild type 181 wild type, 139 white You also self several wild-type plants from the F2 and determine that some of them are pure-breeding. What can you conclude from these results? For each statement, choose the correct response by selecting only from the three answer choices to the left of that statement. Drag the correct answer to the right of each statement. ► View Available Hint(s) Reset Heln
Part A - Crossing lines with the same recessive phenotype You continue your analysis by crossing the Aberdeen White and Victoria White lines. This time you count the actual numbers of progeny in the two F2 phenotypic classes. F₂ phenotypes and numbers dominant epistasis independent assortment recessive epistasis complementary gene action You also self several wild-type plants from the F₂ and determine that some of them are pure-breeding. What can you conclude from these results? For each statement, choose the correct response by selecting only from the three answer choices to the left of that statement. Drag the correct answer to the right of each statement. ▸ View Available Hint(s) dominant epistasis recessive epistasis 13:3 9:7 3:1 false true cannot be determined Cross Aberdeen White x Victoria White 1. Aberdeen White and Victoria White are alleles of different loci. 2. The pure-breeding wild-type progeny in the F₂ are the result of 3. The F₂ ratio is approximately 4. The F₂ ratio results from Group 1 Group 2 Group 3 F₁ phenotype Group 4 wild type 181 wild type, 139 white Reset Help
Part B - Crossing lines with dissimilar recessive phenotypes You continue your analysis by crossing the Aberdeen White and Kansas Yellow lines. Again, you count the actual numbers of progeny in the two F₂ phenotypic classes. F₁ phenotype F₂ phenotypes and numbers true failure to complement 3:1 (from a 1:2:1 genotype ratio) What can you conclude from this cross? For each statement, choose the correct response by selecting only from the three answer choices to the left of that statement. Drag the correct answer to the right of each statement. View Available Hint(s) recessive epistasis false recessive epistasis 13:3 (from a 9:3:3:1 genotype ratio) complete dominance cannot be determined dominant epistasis 12:4 (from a 9:3:3:1 genotype ratio) Cross dominant epistasis Aberdeen White x Kansas Yellow 1. Aberdeen White and Kansas Yellow are alleles of different loci. 2. The lack of wild-type progeny in the F₂ is the result of 3. The F₂ ratio is approximately yellow 4. The F₂ ratio results from Reset Help Group 1 Group 2 Group 3 121 yellow, 41 white Group 4
Part C - A second cross between lines with dissimilar phenotypes You complete your analysis by crossing the Victoria White and Kansas Yellow lines. Again, you count the actual numbers true dominant epistasis 12:3:1 dominnat epistasis false recessive epistasis As before, you self several wild-type plants from the F2 and again determine that some of them are pure-breeding. What can you conclude from these results? For each statement, choose the correct response by selecting only from the three answer choices to the left of that statement. Drag the correct answer to the right of each statement. ► View Available Hint(s) 1:2:1 recessive epistasis cannot be determined independent assortment 9:3:4 Cross duplicate gene action Victoria White x Kansas Yellow 1. Victoria White and Kansas Yellow are alleles of different loci. 2. The pure-breeding wild-type progeny in the F₂ are the result of 3. The F₂ ratio is approximately progeny in the F2 phenotypic classes. 4. The F₂ ratio results from F₁ phenotype wild type Group 1 Reset Help Group 2 F₂ phenotypes and numbers Group 3 89 wild type, 39 white, 29 yellow Group 4