Box Without Foam Data A Force N 22222322 24 A Force N 22 20 18 16 14 12 10 8 4 2 2 Box Without Foam 24 22 20 18 F M 1 (374.84 KiB) Viewed 19 times
Box without Foam data: A Force (N 22222322 24 A Force (N 22 20 18 16 14 12 10 8 4 2 · 2 box without foam 24 22 20 18 F(max) = 19.884 N Time t(initial) = 1.435 sec t(final) = 1.461 sec Box with foam data: 16 14 10 B 6 0.8 box with foam 118 120 122 124 126 128 130 132 134 136 138 140 142 144 146 148 150 152 154 156 158 160 162 164 Time(s) 1.0 • ANN Þ» £ ×È **. 11 F(max) = 7.826 N Time: t(initial) = 1.794 s •^A* • < NN Þ»¤×¢ **• 1435 s. 0.028 N 12 1.3 14 1.449 s.19.884 N 1.5 t(final) = 1.887 s 1835 s. 7.826 N 1.794 s.0.055 N 1.6 17 Time (s) . E ** n 1.8 1 19 1461 -0.083 N 1.887 s.0.083N 2.0 2.1 2.2 Run #1 2.3 Run #1 24 Centrale X
Part 1: Impulse - Momentum Theorem foam box Force sensor cart Motion sensor Record the following: Emai _N Duration of collision (At): Now place a piece of foam in front of the box and repeat the above measurements. Emai N Duration of collision (At): 1) Recall the impulse-momentum theorem: Ap = F At Assume that two different cars collide with a brick wall and suffer the same Ap. The airbag deploys in one car and fails to deploy in the other. Why (in terms of Ap, F and At in the above equation) does the driver of one car sustain less injury than the other? 2) Compare the values of Fmax and At for the cart collisions. What difference does the foam make?
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