Problem 1: Glucose isomers Glucose can exist in many isomeric forms. In solution, three of the most abundant isomers of

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Problem 1 Glucose Isomers Glucose Can Exist In Many Isomeric Forms In Solution Three Of The Most Abundant Isomers Of 1 (48.8 KiB) Viewed 27 times

Problem 1 Glucose Isomers Glucose Can Exist In Many Isomeric Forms In Solution Three Of The Most Abundant Isomers Of 2 (27.45 KiB) Viewed 27 times

Problem 1: Glucose isomers Glucose can exist in many isomeric forms. In solution, three of the most abundant isomers of glucose are D-Glucose, a-D glucose and B-D glucose. At a temperature of 270 K their relative abundances are given by the proportions D-glucose: a-D glucose: B-D glucose = 1 : 142: 266 (i.e. for every 1 molecule of D-glucose there are 142 molecules of a-D glucose and 266 molecules of B-D glucose). We can use these abundances as a proxy for their multiplicities: we don't know what their multiplicities actually are, but we can assume the ratio between the multiplicities is the same as their relative abundances. A. Determine the difference in entropy (in J/[mol - K]) between the D and a-D forms, i.e. Sa-D-SD- B. Determine the difference in entropy (in J/[mol · K]) between the D and B-D forms, i.e. SB-D-SD- C. Suppose that the three forms all had exactly the same enthalpy, i.c. AH = 0 between any two forms. Given your answers above, which of the forms would have: 1. The highest Gibbs free energy? 2. The lowest Gibbs free energy?
The three forms do not actually have the same enthalpy, because their bond structure changes between each isomer (changing the total energy stored in the bond arrangement). Thus, to change between isomers requires flexing some of the bonds, changing their enthalpy. The change in Gibbs free energy between the isomers is: kJ AGp-a-D= = -11.63 AGD-8-D = -13.1 mol kJ mol D. Determine the difference in the enthalpy between the D and a-D forms, i.c., H₂-D - Hp. E. Determine the difference in enthalpy between the a-D and B-D forms, i.e., Hg-D-Ha-D-