Given: c = 2.998 108 m/s 1. A grain of black carbon dust with a mass of 6.55x10-6 kg and a cross-sectional area of 5.9x1

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Given: c = 2.998 108 m/s 1. A grain of black carbon dust with a mass of 6.55x10-6 kg and a cross-sectional area of 5.9x1

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Given C 2 998 108 M S 1 A Grain Of Black Carbon Dust With A Mass Of 6 55x10 6 Kg And A Cross Sectional Area Of 5 9x1 1
Given C 2 998 108 M S 1 A Grain Of Black Carbon Dust With A Mass Of 6 55x10 6 Kg And A Cross Sectional Area Of 5 9x1 1 (47.57 KiB) Viewed 25 times
Given: c = 2.998 108 m/s 1. A grain of black carbon dust with a mass of 6.55x10-6 kg and a cross-sectional area of 5.9x10-13 mºis at a location in interplanetary space where the intensity of solar radiation is 2420 W/m². The Sun's gravity at this location exerts an attractive force of 6.90 10-18 N on the grain. a) Calculate the radiation pressure exerted by sunlight on the grain. b) What are the magnitude and direction (toward or away from the Sun) of the grain's acceleration? 2. A beam of unpolarized light with an intensity of 2800 W/m passes through two polarizers, The transmission axis of the first polarizer is +20.0° from vertical, and the transmission axis of the second polarizer is +52.5° from vertical. a) What is the intensity of the beam after passing through the second polarizer? b) At what two angles (relative to vertical) could the transmission axis of a third polarizer be oriented, so that the resulting beam has an intensity of 929 W/m²?
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