- Use The Graph To Find The Following Limits And Function Value A Lim F X X 0 B Lim F X X 0 C Lim F X X 0 D F 0 1 (29.05 KiB) Viewed 5 times
- Use The Graph To Find The Following Limits And Function Value A Lim F X X 0 B Lim F X X 0 C Lim F X X 0 D F 0 2 (21.34 KiB) Viewed 5 times
- Use The Graph To Find The Following Limits And Function Value A Lim F X X 0 B Lim F X X 0 C Lim F X X 0 D F 0 3 (23.15 KiB) Viewed 5 times
- Use The Graph To Find The Following Limits And Function Value A Lim F X X 0 B Lim F X X 0 C Lim F X X 0 D F 0 4 (43.62 KiB) Viewed 5 times
- Use The Graph To Find The Following Limits And Function Value A Lim F X X 0 B Lim F X X 0 C Lim F X X 0 D F 0 5 (33.65 KiB) Viewed 5 times
Use the graph and the function to find the following. a) Find lim k(x). X-1 b) Find k(1). c) Isk continuous at x = 17 a) Select the correct choice below and fill in any answer boxes in your choice. OA lim k(x)= X-1 (Round to the nearest integer as needed.) OB. The limit does not exist. 7-5-4-3- 5 4 3 y=k[x] 2 Al -01- +2+ 3 +4 SE
Use the graph to answer these questions. a. Find lim f(x) and lim f(x). X-3 b. Find lim f(x). x-3 c. Find (3). d. Is f(x) continuous at x = 3? Why or why not? 10- a. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. lim f(x)= (Simplify your answer.) x→3* B. The limit does not exist. y=f(x) X
Is the function given below continuous at x = 5? Why or why not? f(x) = 9x-5 Is f(x) = 9x-5 continuous at x = 5? Why or why not? OA. Yes, f(x) is continuous at x = 5 because lim f(x) is equal to f(5). X-5 OB. No, f(x) is not continuous at x = 5 because lim f(x) and f(5) do not exist. X-5 OC. Yes, f(x) is continuous at x = 5 because f(5) exists. OD. No, f(x) is not continuous at x = 5 because lim f(x) is not equal to f(5). X-5 ....
Is the function given by f(x) = 5x+2, for x s5, 3x-12, for x>5, Choose the correct answer below. continuous at x = 5? Why or why not? OA. The given function is not continuous at x = 5 because f(5)= lim f(x) = 3. X-5 OB. The given function is continuous at x = 5 because f(5) = lim f(x) = 3. X-5 OC. The given function is not continuous at x = 5 because the limit does not exist. OD. The given function is continuous at x = 5 because f(5) does not exist.