- 4 2 Points Let S Be The Solid In The Second Octant Z 0 Y 0 Z 0 Bounded By Z Y X Y 4 And Th 1 (15.86 KiB) Viewed 16 times
4. (2 points) Let S be the solid in the second octant (z ≤ 0, y ≥ 0, z ≥ 0) bounded by z = √√² + y², x² + y² = 4, and th
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4. (2 points) Let S be the solid in the second octant (z ≤ 0, y ≥ 0, z ≥ 0) bounded by z = √√² + y², x² + y² = 4, and th
4. (2 points) Let S be the solid in the second octant (z ≤ 0, y ≥ 0, z ≥ 0) bounded by z = √√² + y², x² + y² = 4, and the coordinate planes. Set up, do not solve, integrals in the following coordinate systems to integrate f(x, y, z) = 6x-2² over S. (a) cylindrical (b) spherical