Find The Equation Of The Tangent Plane To The Surface Z 5x5 6y5 4xy At The Point 2 3 1594 2 Find The Lin 1 (10.06 KiB) Viewed 9 times
Find the equation of the tangent plane to the surface z = 5x5 + 6y5 + 4xy at the point (-2, -3, -1594). 2=
Find the linearization of the function 2 z=x√y at the point (1, 1). L(x, y) =
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!