fxxy(x, y) ƒ(x, y) = sin(2x5 + 3y¹)

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answerhappygod
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fxxy(x, y) ƒ(x, y) = sin(2x5 + 3y¹)

Post by answerhappygod »

Fxxy X Y F X Y Sin 2x5 3y 1
Fxxy X Y F X Y Sin 2x5 3y 1 (7.61 KiB) Viewed 9 times
for the function
Fxxy X Y F X Y Sin 2x5 3y 2
Fxxy X Y F X Y Sin 2x5 3y 2 (8.35 KiB) Viewed 9 times
(Please show complete process, thank you)
fxxy(x, y)
ƒ(x, y) = sin(2x5 + 3y¹)
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