4) Determine where the function is continuous. a) f(x, y) = x² y √16-x² - y² ху b) ƒ(x, y) = { x² + xy + y² ›(x, y) ± (0

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answerhappygod
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4) Determine where the function is continuous. a) f(x, y) = x² y √16-x² - y² ху b) ƒ(x, y) = { x² + xy + y² ›(x, y) ± (0

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4) Determine where the function is continuous. a) f(x, y) = x² y √16-x² - y² ху b) ƒ(x, y) = { x² + xy + y² ›(x, y) ± (0, 0) 0, (x, y) = (0,0)
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