Entered (2e^2cos(t)-e^(2t)sin(t))i+ (2e^(2t)sin(t)+e^(2t)j+2e^(2t)k 3*[e^(2*t)] (((-2sin(t)-cos(t))/3)i+2cos(t)- sin(t))

[answerhappygod]

Entered 2e 2cos T E 2t Sin T I 2e 2t Sin T E 2t J 2e 2t K 3 E 2 T 2sin T Cos T 3 I 2cos T Sin T 1 (94.82 KiB) Viewed 11 times

Entered (2e^2cos(t)-e^(2t)sin(t))i+ (2e^(2t)sin(t)+e^(2t)j+2e^(2t)k 3*[e^(2*t)] (((-2sin(t)-cos(t))/3)i+2cos(t)- sin(t))/3)j +0k ([-2*sin(t)-cos(t)]/[sqrt(5)])*i+ ([2*cos(t)- sin(t)]/[sqrt(5)])*j+0*k Answer Preview -2 sin(t) – cos(t) √5 3e²t ∙i+ 2 cos(t) = sin(t) √5 -j+0k Result incorrect correct incorrect correct Message Operands for '+' must be of the same type Operands for '+' must be of the same type