Test: Test 6 - Chapter 8 Test of p = 0.91 vs p *0.91 Sample X N 2,013 1 1938 A poll of 2,013 randomly selected adults sh

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Test Test 6 Chapter 8 Test Of P 0 91 Vs P 0 91 Sample X N 2 013 1 1938 A Poll Of 2 013 Randomly Selected Adults Sh 1 (195 KiB) Viewed 9 times

Test: Test 6 - Chapter 8 Test of p = 0.91 vs p *0.91 Sample X N 2,013 1 1938 A poll of 2,013 randomly selected adults showed that 96% of them own cell phones. The technology display below results from a test of the claim that 91% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Sample p 0.962742 a. Is the test two-tailed, left-tailed, or right-tailed? O Left-tailed test OTwo-tailed test O Right tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? OB. Hg: p=0.91 O C. Hg: p>0.91 95% CI (0.954469,0.971016) The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. OA. Ho: p<0.91 Textbook Statcrunch Tech help Z-Value 8.27 Question 2 of 4 P-Value 0.000 > This test: 4 point(s) possible This question: 1 point(s) possible Submit test Next