- Let X 032 Be The Dtft Of The Following Signal N 25 N 2 N 25 N 1 26 N 30 5n 4 25 N 6 1 (29.77 KiB) Viewed 38 times
Let X (032*/) be the DTFT of the following signal. [n] = -25\n + 2 - [n] + 25 [n - 1+ 26[n – 30 - 5n – 4] - 25[n – 6]. (
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Let X (032*/) be the DTFT of the following signal. [n] = -25\n + 2 - [n] + 25 [n - 1+ 26[n – 30 - 5n – 4] - 25[n – 6]. (
Let X (032*/) be the DTFT of the following signal. [n] = -25\n + 2 - [n] + 25 [n - 1+ 26[n – 30 - 5n – 4] - 25[n – 6]. (a) Find X(1) = X(elº). (b) Find a such that e2708 X (278) is real. hint: plot the sequence x[n] before answering this part. (c) Find X (1245) df. -1/2 (d) Find X (en) 1/2 (e) Evaluate the following integral: L 1x (2325)]* of -1/2 (f) Evaluate the following integral: 11/2 ax (032-6) df df -1/2