за) 5x+2 =-х b) (3-√8) (7 + √2) express in the form a +b√z Selve 12x-71 = 30C+2] d) radius of a circle. Centre equation

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answerhappygod
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за) 5x+2 =-х b) (3-√8) (7 + √2) express in the form a +b√z Selve 12x-71 = 30C+2] d) radius of a circle. Centre equation

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за) 5x+2 =-х b) (3-√8) (7 + √2) express in the form a +b√z Selve 12x-71 = 30C+2] d) radius of a circle. Centre equation of tangent/normal
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