Mainly Show your work

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answerhappygod
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Mainly Show your work

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Mainly Show your work
Mainly Show Your Work 1
Mainly Show Your Work 1 (61.86 KiB) Viewed 15 times
The signal x(t) = sin(&t) + sin(It) has period T = 8 and Fourier coefficients = ak = 16 7 – 16k27 The signal y(t) has period T = 8 and the Fourier coefficients bk = 4 - 16k27 = = = What is the expression for y(t)? y(t) = sin(at)| + sin(at) +1. y(t) = à sin(61)| + sin(Qt). y(t) = 1 sin(#(t + 1))| + sin(4 (t+1)). Oy y(t) = sin( 7 (t + 1))| + sin( (t+1)). y(t) = sin(4 (t – 2))| + sin(A(t – 2)). y(t) = sin((t+1))| + sin((t + 1)) – 16. Oy(t) = sin(İ (t – 2)) + sin( 7 (t – 2) + 16 Oy(t) = sin(İ (t – 2))] + sin(#(t – 2)) – 16 = = - = - IT =
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