X(lambda)=sin(2*lambda*alpha) and Y(lambda)=lambda*sin(2*alpha). The characteristic equation is: X(lambda)-Y(lambda)=0.
Posted: Wed Jul 06, 2022 11:55 am
X(lambda)=sin(2*lambda*alpha) and Y(lambda)=lambda*sin(2*alpha).The characteristic equation is: X(lambda)-Y(lambda)=0.
When alpha=3*pi/4, what are the roots (zeros) for thisvalue of alpha? Find the roots both graphically from plotting thevalues of lambda from zero to one and via the root findingalgorithm (Newton-Raphson) to calculate the roots that result instress singularities. There should be three values.
When alpha=3*pi/4, what are the roots (zeros) for thisvalue of alpha? Find the roots both graphically from plotting thevalues of lambda from zero to one and via the root findingalgorithm (Newton-Raphson) to calculate the roots that result instress singularities. There should be three values.