X(lambda)=sin(2*lambda*alpha) and Y(lambda)=lambda*sin(2*alpha). The characteristic equation is: X(lambda)-Y(lambda)=0.

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answerhappygod
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X(lambda)=sin(2*lambda*alpha) and Y(lambda)=lambda*sin(2*alpha). The characteristic equation is: X(lambda)-Y(lambda)=0.

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X(lambda)=sin(2*lambda*alpha) and Y(lambda)=lambda*sin(2*alpha).The characteristic equation is: X(lambda)-Y(lambda)=0.
When alpha=3*pi/4, what are the roots (zeros) for thisvalue of alpha? Find the roots both graphically from plotting thevalues of lambda from zero to one and via the root findingalgorithm (Newton-Raphson) to calculate the roots that result instress singularities. There should be three values.
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