Consider a 1.00m long string, with linear density -0.00800 kg/m, under a 20.0 N tension. The string is set to oscillate

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answerhappygod
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Consider a 1.00m long string, with linear density -0.00800 kg/m, under a 20.0 N tension. The string is set to oscillate

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Consider A 1 00m Long String With Linear Density 0 00800 Kg M Under A 20 0 N Tension The String Is Set To Oscillate 1
Consider A 1 00m Long String With Linear Density 0 00800 Kg M Under A 20 0 N Tension The String Is Set To Oscillate 1 (17.43 KiB) Viewed 16 times
Consider A 1 00m Long String With Linear Density 0 00800 Kg M Under A 20 0 N Tension The String Is Set To Oscillate 2
Consider A 1 00m Long String With Linear Density 0 00800 Kg M Under A 20 0 N Tension The String Is Set To Oscillate 2 (38.24 KiB) Viewed 16 times
Consider a 1.00m long string, with linear density -0.00800 kg/m, under a 20.0 N tension. The string is set to oscillate in the 6th harmonic. a) (3pt) Find the frequency of oscillation of the string. Answer: b) (pt) Find the wavelength of oscillation of the string. Answer: d (6pt) What is the wavelength of the sound wave produced by the string. Answer: d) (7pt) (Consider that the string excites the 2nd mode of an open-closed tube that is next to the string. What is the length of the tube? Answer:
You are on a planet for which you do not know the value of the acceleration of gravity, and your goal is to find that value by performing the following experiment: you set up a pendulum by using a very light string with a mass hanging. You measure the period of oscillation for different lengths. You know that the equation for the pendulum is the same as on earth, so you plot the period squared vs. the length of the pendulum and you fit the data using a linear trend equation. Use the trend line information to find the gravity on the planet. Answer: Hint: square the equation for the pendulum and rearrange it according to the graph Period squared (s²) 160 140 120 100 80 60 40 20 0 0 2 T2 vs L y = 7.8722x + 0.0011 6 8 10 Length (meters) 12 14 16 18
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