Consider a clear liquid in an open container. We determine that the liquid-air critical angle is 44°. If light is shined

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Consider A Clear Liquid In An Open Container We Determine That The Liquid Air Critical Angle Is 44 If Light Is Shined 1 (25.07 KiB) Viewed 11 times

Consider a clear liquid in an open container. We determine that the liquid-air critical angle is 44°. If light is shined from above the container at varying values of the angle of incidence ₁, an orientation ₂ = 0, will be found where r = 0. Find 0p. • Show your work in the below text box. • To write √ use this notation in the below text box: "sqrt(x)" Remarks: • You must type all the steps of your detailed calculation in the below text box. • A final answer will NOT be accepted if the detailed calculation steps are missing in the below text box. • Files submitted by email are NOT accepted; your detailed answer must be exclusively written in the below text box.