Time left 0:59:12 7 =( [20 points] A particle of charge of 6 x 10-9 [C] is moving with a velocity equal to → 8 x 105)-(3

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Time Left 0 59 12 7 20 Points A Particle Of Charge Of 6 X 10 9 C Is Moving With A Velocity Equal To 8 X 105 3 1 (95.44 KiB) Viewed 14 times

Time left 0:59:12 7 =( [20 points] A particle of charge of 6 x 10-9 [C] is moving with a velocity equal to → 8 x 105)-(3 × 105) +(6 × 105) 2 [m/s] is in a region of magnetic field given by B = 0.6 +0.3 -0.4 k [T]. A magnetic force F will be applied on the particle. →> a) [5 points] Find the F, the x-component of F F₁ = [N] b) [5 points] Find the Fy, the y-component of F [N] c) [5 points] Find the F₂, the z-component of F F₂ = [N] d) [5 points] Find the magnitude of magnetic force F F = [N] Pr