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answerhappygod
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thank you for answer the question.

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thank you for answer the question.
Thank You For Answer The Question 1
Thank You For Answer The Question 1 (257.46 KiB) Viewed 10 times
Thank You For Answer The Question 2
Thank You For Answer The Question 2 (187.44 KiB) Viewed 10 times
1. [-/1 Points] A rod 10.0 cm long is uniformly charged and has a total charge of -21.0 μC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 34.0 cm from its center. magnitude N/C direction ---Select--- 2. [-/1 Points] DETAILS DETAILS SERPSE10 23.1.OP.001. E = A continuous line of charge lies along the x axis, extending from x = +x to positive infinity. The line carries positive charge with a uniform linear charge density. (a) What is the magnitude of the electric field at the origin? (Use the following as necessary: o, xo, and k.) O (b) What is the direction of the electric field at the origin? O +X O -X SERPSE10 23.1.P.007. +y -Y O +z O -Z
3. [-/1 Points] DETAILS SERPSE10 23.1.OP.003.MI. A uniformly charged insulating rod of length 20.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of -7.50 pc. D (a) Find the magnitude of the electric field (in N/C) at O, the center of the semicircle. N/C (b) Find the direction of the electric field at O, the center of the semicircle. O to the left to the right O upward Odownward O into the page O out of the page (c) What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried a total charge of -7.50 μC and the bottom half, insulated from the top half, carried a total charge of +7.50 μC? N/C (d) What would be the direction of the electric field at O if the top half of the semicircle carried a total charge of -7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC? O to the left O to the right O upward O downward O into the page O out of the page MY
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