You are given the equation used to solve a problem: (9.0×10 Nm²/C²)(3.0x10- C) (9.0x10 Nm²/C²)(3.0×10-⁹ C) + (0.030 m) +

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You Are Given The Equation Used To Solve A Problem 9 0 10 Nm C 3 0x10 C 9 0x10 Nm C 3 0 10 C 0 030 M 1 (66.67 KiB) Viewed 9 times

You are given the equation used to solve a problem: (9.0×10 Nm²/C²)(3.0x10- C) (9.0x10 Nm²/C²)(3.0×10-⁹ C) + (0.030 m) + d 0.030 m = 1200 V Two 3.0 nC charges are distance 3.0 mm apart. At a point d from one charge, Oon the side opposite the other charge, the potential is 1200 V. Find the separation d between the charges. Two 3.0 nC charges are distance d apart. At a point 3.0 mm from one charge, Oon the side opposite the other charge, the potential is 1200 V. Find the separation d between the charges. Submit ✓ Correct Part B Previous Answers Finish the solution of the problem. Express your answer with the appropriate units. ■² μA A d = .06 Submit Units Previous Answers Request Answer ? X Incorrect; Try Again; 4 attempts remaining Check that you have converted between SI units of distance correctly.