21. 22. 23. 24. •N₂O 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 12 g 1 mol He 2 mol Na H₂O 27,2% 5 mol He 6.9 g Li 36 g

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answerhappygod
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21. 22. 23. 24. •N₂O 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 12 g 1 mol He 2 mol Na H₂O 27,2% 5 mol He 6.9 g Li 36 g

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21 22 23 24 N O 25 26 27 28 29 30 31 32 33 34 35 12 G 1 Mol He 2 Mol Na H O 27 2 5 Mol He 6 9 G Li 36 G 1
21 22 23 24 N O 25 26 27 28 29 30 31 32 33 34 35 12 G 1 Mol He 2 Mol Na H O 27 2 5 Mol He 6 9 G Li 36 G 1 (43.36 KiB) Viewed 10 times
21. 22. 23. 24. •N₂O 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 12 g 1 mol He 2 mol Na H₂O 27,2% 5 mol He 6.9 g Li 36 g C 2 mol Ca 2 mol Na 62 g P 41 g BeS Mole to mole 10 moles 24.3 g 2 mol He 4 mol C CO₂ H₂O; 36.3% 2 mol Ne 32.1 g S 42 g N 4 mol Ca 4 mol Na 193 g P 123 g Bes Mass to mass 14 moles is the mass of 1 mol Mg. has a greater mass. has a mass greater than 50.0 g. has a molar mass of 44 g/mol. has a greater percentage of hydrogen by mass. is the percentage of C in CO₂. is more massive than 3 mol Be. has the same number of atoms as 24.3-g of Mg. represents 3 mol substance. is the stoichiometric equivalence of 4 mol S according to the equation, Ca+S-CaS. is the stoichiometric equivalence of 2 mol S according to the equation, 2Na+S → Na S. is the stoichiometric equivalence of 81 g Al according to the equation, Al + PAIP. will be produced by the reaction of 27 g of Be with its stoichiometric equivalence of S according to the equation. Be+ S BeS, Note: Round molar masses to the nearest whole number. ratios are provided by a balanced chemical equation. of Y can be produced by the reaction of 8 moles of X, according to the equation, 4X→ 7Y. 44 F7 DII FB DD F9 A F10 I 3 F11
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