One way of expressing the rate at which an enzyme can catalyze a reaction is to state its turnover number. The turnover

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One Way Of Expressing The Rate At Which An Enzyme Can Catalyze A Reaction Is To State Its Turnover Number The Turnover 1 (96.9 KiB) Viewed 13 times

One way of expressing the rate at which an enzyme can catalyze a reaction is to state its turnover number. The turnover number is the maximum number of substrate molecules that can be acted on by one molecule of enzyme per unit of time. The table gives the turnover number of four representative enzymes. Enzyme Ribonuclease Fumarase Lactate dehydrogenase Urease How many molecules of fumarate can one molecule of fumarase act on in 13.4 min ? fumarate molecules: 9000000 Substrate Turnover number (per second) RNA 100 fumarate 800 lactate 1000 urea 10,000 Incorrect
The protein catalase catalyzes the reaction 2 H,O,(aq) 2 H₂O(l) + O₂(g) and has a Michaelis-Menten constant of KM = 25 mM and a turnover number of 4.0 x 107 s-¹. The total enzyme concentration is 0.017 µM and the initial substrate concentration is 6.10 µM. Catalase has a single active site. Calculate the value of Rmax (often written as Vmax) for this enzyme. Rmax = R = 1360 Incorrect Calculate the initial rate, R (often written as Vo), of this reaction. 0.3317 Incorrect mM-s-1 mM-s-1
The Michaelis-Menten equation models the hyperbolic relationship between [S] and the initial reaction rate Vo for an enzyme-catalyzed, single-substrate reaction E+ SES → E + P. The model can be more readily understood when comparing three conditions: [S] << Km, [S] = Km, and [S] >> Km. Match each statement with the condition that it describes. Note that "rate" refers to initial velocity Vo where steady state conditions are assumed. [Etotal] refers to the total enzyme concentration and [Efree] refers to the concentration of free enzyme. [S] << Km [ES] is much lower than [Efree]. [Efree] is about equal to [Etotal]. Incorrect [S] = Km This condition rarely occurs for most in vivo enzymes. [Efree] is equal to [ES]. [S] >> Km Almost all active sites will be filled. Answer Bank Not true for any of these conditions Increasing [Etotal] will lower Km.