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The entropy increase produced by mixing two liquids is based on the formula for the entropy change that results from the isothermal expansion of a fluid from volume Vential to volume V ASnRin(). Suppose two liquids are mixed together to make a binary solution. One liquid has initial volume V₁ and the second liquid has initial volume V₂. Assume there is no change in the volumes of the individual liquids and if the liquids mix randomly the final volume is exactly Vjoi = V₁ + V₂. Then the total entropy change for mixing the two liquids is: $₁ = ASme=AS₁ + AS, = -R(nin+₂) = R(n. Ind+nInd) where and are x = the volume tractions of liquids 1 and 2, respectively. Note like mole fractions volume fractions must sum to one: +1. ▾ Part B Suppose 1:00 moi of liquid 1 is mixed with 2.00 molas of liquid 2. Assume V₁ == 1.80 x 10 mmol ¹ Calculate the volume fraction of liquid 1. -ΘΕ ΑΣΦ + A C P ? -0.667 Submit Previous Answers Request Answer ▾ Part C * Incorrect; Try Again; 4 attempts remaining Using your results from Part B, calculate the entropy of mixing. ▾ ASmix ✓ Submit Part D X1- Submit Part E For the liquids described in Part B, calculate the mole fraction for liquid 1, i.e. Xi. p= DA + • C MAI ? Value Submit Part F Request Answer IVE ΑΣΦ ← A C 1503 ? The parameter x = measures the relative size of the two types of molecules. If molecules 1 and 2 are roughly the same size, z 1. But il molecule 2 is much larger than molecule 1, 2 > 1. Assume that 1 mole of liquid 1 is mixed with 2 moles of lquid 2. but assume also a 10. Calculate the volume fraction ΙΠ ΑΣΦ Request Answer ASmiz = Units Request Answer CH 1 → O Using your results from part E, calculate the entropy of mixing. Value Submit Request Answer ? A A C Units ?