For the reaction 6CO2 (g) + 6H₂O(l) → C6H12O6 +602(g) AH° 2800.8 kJ and AS = 259.0 J/K The standard free energy change f

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

For the reaction 6CO2 (g) + 6H₂O(l) → C6H12O6 +602(g) AH° 2800.8 kJ and AS = 259.0 J/K The standard free energy change f

Post by answerhappygod »

For The Reaction 6co2 G 6h O L C6h12o6 602 G Ah 2800 8 Kj And As 259 0 J K The Standard Free Energy Change F 1
For The Reaction 6co2 G 6h O L C6h12o6 602 G Ah 2800 8 Kj And As 259 0 J K The Standard Free Energy Change F 1 (31.1 KiB) Viewed 9 times
For The Reaction 6co2 G 6h O L C6h12o6 602 G Ah 2800 8 Kj And As 259 0 J K The Standard Free Energy Change F 2
For The Reaction 6co2 G 6h O L C6h12o6 602 G Ah 2800 8 Kj And As 259 0 J K The Standard Free Energy Change F 2 (23.64 KiB) Viewed 9 times
For the reaction 6CO2 (g) + 6H₂O(l) → C6H12O6 +602(g) AH° 2800.8 kJ and AS = 259.0 J/K The standard free energy change for the reaction of 2.02 moles of CO2 (g) at 296 K, 1 atm would be kJ. favored under This reaction is standard conditions at 296 K. Assume that AHⓇ and AS° are independent of temperature.
For the reaction I2 (g) + Cl₂(g) → 2IC1(g) AG = -29.7 kJ and AS° = 11.4 J/K at 251 K and 1 atm. This reaction is product favored under standard conditions at 251 K. The standard enthalpy change for the reaction of 2.48 moles of I₂ (g) at this temperature would be KJ.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply