Question 4 (16 pts) NA = 6.022 x 1023 items/mol A) Calculate the formula mass of Ni(NO3)3 B) How many moles of Ni(NO3)3

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Question 4 (16 pts) NA = 6.022 x 1023 items/mol A) Calculate the formula mass of Ni(NO3)3 B) How many moles of Ni(NO3)3

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Question 4 (16 pts) NA = 6.022 x 1023 items/mol A) Calculate theformula mass of Ni(NO3)3 B) How many moles of Ni(NO3)3 are presentin a 450. g sample? C) How many moles of Ni and O are present inpart B? Ni __________________ O __________________ D) How manyatoms of Ni are present in part B (or part C).
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