A cable lifts a 1010-kg elevator at a constant velocity for a distance of 33.1 m. What is the work done by (a) the tensi

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answerhappygod
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A cable lifts a 1010-kg elevator at a constant velocity for a distance of 33.1 m. What is the work done by (a) the tensi

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A Cable Lifts A 1010 Kg Elevator At A Constant Velocity For A Distance Of 33 1 M What Is The Work Done By A The Tensi 1
A Cable Lifts A 1010 Kg Elevator At A Constant Velocity For A Distance Of 33 1 M What Is The Work Done By A The Tensi 1 (34.85 KiB) Viewed 5 times
A Cable Lifts A 1010 Kg Elevator At A Constant Velocity For A Distance Of 33 1 M What Is The Work Done By A The Tensi 2
A Cable Lifts A 1010 Kg Elevator At A Constant Velocity For A Distance Of 33 1 M What Is The Work Done By A The Tensi 2 (49.95 KiB) Viewed 5 times
A Cable Lifts A 1010 Kg Elevator At A Constant Velocity For A Distance Of 33 1 M What Is The Work Done By A The Tensi 3
A Cable Lifts A 1010 Kg Elevator At A Constant Velocity For A Distance Of 33 1 M What Is The Work Done By A The Tensi 3 (41.87 KiB) Viewed 5 times
A Cable Lifts A 1010 Kg Elevator At A Constant Velocity For A Distance Of 33 1 M What Is The Work Done By A The Tensi 4
A Cable Lifts A 1010 Kg Elevator At A Constant Velocity For A Distance Of 33 1 M What Is The Work Done By A The Tensi 4 (21.79 KiB) Viewed 5 times
A cable lifts a 1010-kg elevator at a constant velocity for a distance of 33.1 m. What is the work done by (a) the tension in the cable and (b) the elevator's weight? (a) Number i (b) Number Units Units
A water skier, moving at a speed of 6.17 m/s, is being pulled by a tow rope that makes an angle of 36.3 ° with respect to the velocity of the boat (see the drawing). The tow rope is parallel to the water. The skier is moving in the same direction as the boat. If the tension in the tow rope is 156 N, determine the work that it does in 12.5 s. Number i Units <>
The skateboarder in the figure is coasting down a ramp, and there are three forces acting on her: her weight W (magnitude = 684 N), a frictional force (magnitude = 136N) that opposes her motion, and a normal force (magnitude = 634 N). Determine the net work done (a) by the N weight W, (b) by the frictional force, and (c) by the normal force FN when she coasts for a distance of 11.8 m. 20 22.0° W FN
(a) Number 22.0° (a) i (b) Number i (c) Number i W FN Units Units Units () (> 0=
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