- Sample Number Area M Bucket Shot Weight N Force On Pasta N Sample Number Area M Bucket Shot Weight N 1 E 1 (226.57 KiB) Viewed 17 times
- Sample Number Area M Bucket Shot Weight N Force On Pasta N Sample Number Area M Bucket Shot Weight N 1 E 2 (296.08 KiB) Viewed 17 times
- Sample Number Area M Bucket Shot Weight N Force On Pasta N Sample Number Area M Bucket Shot Weight N 1 E 3 (286.02 KiB) Viewed 17 times
- Sample Number Area M Bucket Shot Weight N Force On Pasta N Sample Number Area M Bucket Shot Weight N 1 E 4 (308.73 KiB) Viewed 17 times
Sample number Area (m²) Bucket & shot weight (N) Force on pasta (N) Sample number Area (m²) Bucket & shot weight (N) 1 Editor Suggestions: Showing 11409.03 Angel Hair 0.636172 0.636172 512 512 2 7 7592.94 3 Thin Spaghetti 8 0.636172 1.130973 512 355 22818.06 15185.88 19835.82 38965.32 4 9917.91 19482.66 9 10 1.539380 1.539380 1.539380 2.010619 4 298 Vermicelli 5 1.130973 355 14234.31 28468.62 Spaghetti 11 2.010619 298 22513.95 28242.99 27772.11 29096.46 30509.1 Force on pasta (N) 45027.9 56485.98 55544.22 58192.92 61018.2 6 1.130973 355 20100.69 40201.38 12 2.010619 298 29655.63 59311.26
Sample number Stress in pasta (MPa) Stress average (MPa) Sample number Stress in pasta (MPa) Stress average (MPa) 1 Angel Hair 7 2 0.03586 0.02387 7724 0695 0.070131732 Thin Spaghetti 8 0.02925 0.03669 0665 3971 0.03117 0.03445 9939 2907 Relationship Between Force and Diar 0.077972033 9 0.03608 2193 10 Vermicelli 5 0.02517 1787 0.071473302 Spaghetti 11 0.02894 0.03034 2784 7963 0.069123747 6 0.03554 5824 12 0.02949 9001
as a function of the pasta diameter for all 12 sa Figure 4 is a log-log plot of the data shown in Figure 3, which plots the force needed to break the pasta vs the pasta diameter. The line of best fit for the data in Figure 4 is log F=###log d + ###. Rearranging Equation (6), to solve for force: US Editor Suggestions Showing log F = log d### + log(###), log F = log (d### ###), F = ###d###, π _### F = ### d 4 Equation (7) is a power-law fit to the force and diameter data presented in Table 1 and Table 2, respectively. Force Required to Break Pasta as Diameter Increases Log-Log Plot) 1000.00 N-338132 # (6) Ñ
Force on Pasta (N) 0.1 Force Required to Break Pasta as Diameter Increases (Log-Log Plot) 100000 y = 33813x R = 0.9667- 10000 Diameter(mm) Force on pasta (N) Linear (Force on pasta (N)) Figure 4: This is a plot of log(force) vs log(din 10