Linearly Polarized Incident Wave E Component On X Z Plane Ex Cos Epe Id Reflected Wave Et 1 40 Jez Nos 1 (79.6 KiB) Viewed 8 times
Linearly polarized incident wave (E₁: component on x-z plane), Ex= cos Epe -id₁ Reflected wave: ÊT (€1, /40) Jez. nos " 1 By ==Epe-i = cos Re-i81 By " U1 where 8₁= w/t = x 1 -R₂e-i8₁ V1 Refracted wave: Er = cos XD₂e-¹₂, By = x siny + z cos v1 (w) ¹-Dp V2 -i8₂ " (11) (9) (10) Boundary conditions: Ex(x, z = 0, t) + Êx (x, z = 0,t) = Ē₁(x, z = 0,t), (12) By(x, z = 0, t) + By (x, z = 0, t) = By(x, z = 0, t), (13)
By Snell's law and boundary conditions, we obtained the following equa- tions among the amplitudes of incident, reflected and refracted waves: (€₁,440) Xezno) Ep cos – Rp cos y = Dp cos X, 1 1 - Ep + = Rp V1 1 V1 x -Dp P V2 If Ep is given, express Dp by Ep and angles (14) (15) and X.
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