Determine the force in each member of the loaded truss. Joint B: AB 45° 15° BC 60° C 30° BX 15⁰ W Joint C: 1 AC 45⁰ SZF₂
Posted: Tue Jul 05, 2022 10:11 am
- Determine The Force In Each Member Of The Loaded Truss Joint B Ab 45 15 Bc 60 C 30 Bx 15 W Joint C 1 Ac 45 Szf 1 (108.77 KiB) Viewed 11 times
Determine the force in each member of the loaded truss. Joint B: AB 45° 15° BC 60° C 30° BX 15⁰ W Joint C: 1 AC 45⁰ SZF₂=0: BC cos 15°- AB cos 45° = 0 BC sin 15° + AB sin 45°- W=0 AB= 1.115 W T BC= 0.816 W с ZFy=0: =0: W 45° 0.816 W 15° B с ZF =0: C Cos 30° + AC cos 60° - 0.816 W cos 15 °=0 Fy=0: -Csin 30° + AC sin 60° -0.816 W sin 15°= 0 AC = 0.577W T c = 0.571 с