Determine The Force In Each Member Of The Loaded Truss Joint B Ab 45 15 Bc 60 C 30 Bx 15 W Joint C 1 Ac 45 Szf 1 (108.77 KiB) Viewed 10 times
My only question is how is AC Gotten, IGNORE THE INITIALQUESTION!Since its my only question, please elaborate!
Determine the force in each member of the loaded truss. Joint B: AB 45° 15° BC 60° C 30° BX 15⁰ W Joint C: 1 AC 45⁰ SZF₂=0: BC cos 15°- AB cos 45° = 0 BC sin 15° + AB sin 45°- W=0 AB= 1.115 W T BC= 0.816 W с ZFy=0: =0: W 45° 0.816 W 15° B с ZF =0: C Cos 30° + AC cos 60° - 0.816 W cos 15 °=0 Fy=0: -Csin 30° + AC sin 60° -0.816 W sin 15°= 0 AC = 0.577W T c = 0.571 с
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