²,500 of I = dx = ["* sec² xdx xPx_³ ² x of = xp +2 89 X co x²

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answerhappygod
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²,500 of I = dx = ["* sec² xdx xPx_³ ² x of = xp +2 89 X co x²

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500 Of I Dx Sec Xdx Xpx X Of Xp 2 89 X Co X 1
500 Of I Dx Sec Xdx Xpx X Of Xp 2 89 X Co X 1 (33.29 KiB) Viewed 9 times
²,500 of I = dx = ["* sec² xdx xPx_³ ² x of = xp +2 89 X co x²
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