- A 3m C Db Dt Dc Dt 2 C Now We Evaluate All The Quantities At The Instant When B 3 Noting That Db Dt 2 B Next W 1 (26.15 KiB) Viewed 10 times
a = 3m C db dt dc dt 2.c. - - Now, we evaluate all the quantities at the instant when b=3, noting that db dt 2 b Next, w
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a = 3m C db dt dc dt 2.c. - - Now, we evaluate all the quantities at the instant when b=3, noting that db dt 2 b Next, w
a = 3m C db dt dc dt 2.c. - - Now, we evaluate all the quantities at the instant when b=3, noting that db dt 2 b Next, we find equations that relate relevant variables. Here we use the Pythagorean Theorem. 2=a² + b² 2- c(t) c(t)=2-b.b(t). ?, Note that a = 3 is a constant, and c and bare functions of time, t. We, then, differentiate both sides of the equation with respect to f, using implicit differentiation when b = 3 2 and that b= 3. Therefore, when b 3.