- 1 Which Ti 83 Or Ti 84 Automatic Calculator Function Will You Use In This Section A 1 Propztest B T Test C X Tes 1 (54.25 KiB) Viewed 10 times
1) Which TI-83+ or TI-84+ automatic calculator function will you use in this section? a) 1-PropZTest b) T-Test c) X²-Tes
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1) Which TI-83+ or TI-84+ automatic calculator function will you use in this section? a) 1-PropZTest b) T-Test c) X²-Tes
1) Which TI-83+ or TI-84+ automatic calculator function will you use in this section? a) 1-PropZTest b) T-Test c) X²-Test d) None of these. 2) When a SRS of 40 people used 'Diet A' for one year, their weight losses had standard deviation 4.9 lbs. Use a 0.01 significance level to test the claim that the population standard deviation of all users of "Diet A' is 6.0, which is the population standard deviation of users of "Diet B. State the null and alternative hypotheses. a) Ho: ≤6.01 Ha: > 6.0 b) Ho:d=6.0 Ha: a = 6.0 3) See problem 2. State the critical value(s) a) 163.691 b) 22.164, 63.191 4) See problem 2. Calculate the test statistic. a) 26.011 b) 58.476 I D Ho:o 26.0 Hao <6.0 c) 20.707,66.766 c) 39.497 d) a) The test statistic is external to the critical value(s): Reject Ho b) The test statistic is external to the critical value(s) FTR Ho c) The test statistic is not external to the critical values); Reject Ho d) The test statistic is not external to the critical value(s); FTR Ho Hold 6.0 Ha:a= 6.0 d) 22.164 5) See problem 2. State the technical conclusion based on the traditional method. d) 41.783 6) See problem 2. State the non-technical conclusion. a) There is sufficient evidence to warrant rejection of the claim that the population standard deviation of all users of 'Diet A' is 6.0, which is the population standard deviation of users of "Diet B. b) There is not sufficient evidence to warrant rejection of the claim that the population standard deviation of all users of "Diet A' is 6.0, which is the population standard deviation of users of Diet 8. c) The sample data support the claim that the population standard deviation of all users of "Diet A' is 6.0, which is the population standard deviation of users of "Diet B