If to 100.0 mL of a buffer that is 0.055 M NH3 (1.8 x 10^-5) and 0.045 M NH4Cl we added 5.00 mL of 1.00 M NaOH solution,

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If to 100.0 mL of a buffer that is 0.055 M NH3 (1.8 x 10^-5) and 0.045 M NH4Cl we added
5.00 mL of 1.00 M NaOH solution, what would be the pH after mixing?
Si a 100.0 mL de un amortiguador que es 0.055 M NH3 (1.8 x 10-5) y 0.045 M NH4Cl se le añaden 5.00 mL de solución 1.00 M NaOH, ¿cuál seria el pH luego de mezclar? O a. 13.75 O b. 3.99 O c. 10.01 O d. 8.50 e. 5.50