As O2() is cooled at 1 atm, it freezes at 63.7 K to form Solid I. At a lower temperature, Solid I rearranges to Solid II
Posted: Tue Jul 05, 2022 9:01 am
As O2() is cooled at 1 atm, it freezes at 63.7 K to form Solid I. At a lower temperature, Solid I rearranges to Solid II, which has a different crystal structure. Thermal measurements show that D H for the 1-ll phase transition is-741.36 J/mol, and AS for the same transition is -16.1 J/K-mol. At what temperature, in K, are Solids I and il in equilibrium? Write the answer with 1 decimal.