- As O2 Is Cooled At 1 Atm It Freezes At 63 7 K To Form Solid I At A Lower Temperature Solid I Rearranges To Solid Ii 1 (13.45 KiB) Viewed 8 times
As O2() is cooled at 1 atm, it freezes at 63.7 K to form Solid I. At a lower temperature, Solid I rearranges to Solid II
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As O2() is cooled at 1 atm, it freezes at 63.7 K to form Solid I. At a lower temperature, Solid I rearranges to Solid II
As O2() is cooled at 1 atm, it freezes at 63.7 K to form Solid I. At a lower temperature, Solid I rearranges to Solid II, which has a different crystal structure. Thermal measurements show that D H for the 1-ll phase transition is-741.36 J/mol, and AS for the same transition is -16.1 J/K-mol. At what temperature, in K, are Solids I and il in equilibrium? Write the answer with 1 decimal.