Lead ions can be precipitated from solution with NaCl according to the following reaction. Pb2+(aq)+2NaCl(aq)→PbCl2(s)+2

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Lead ions can be precipitated from solution with NaCl according to the following reaction. Pb2+(aq)+2NaCl(aq)→PbCl2(s)+2

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Lead ions can be precipitated from solution with NaCl according to the following reaction. Pb2+(aq)+2NaCl(aq)→PbCl2(s)+2Na+(aq) When 135.8 g of NaCl are added to a solution containing 195.7 g of Pb2+, a PbCl2 precipitate forms. The precipitate is filtered and dried and found to have a mass of 254.3 g . Lead ions can be precipitated from solution with NaCl according to the following reaction. Pb2+(aq)+2NaCl(aq)→PbCl2(s)+2Na+(aq) When 135.8 g of NaCl are added to a solution containing 195.7 g of Pb2+, a PbCl2 precipitate forms. The precipitate is filtered and dried and found to have a mass of 254.3 g .
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