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answerhappygod
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Question. Not yet answered Marked out of 15.00 Flag question [15 Points] The figure shows a rod with its central axis along the y-axis and a ring with its central axis along the x-axis. The rod, located at a distance y 13 [cm] from the origin, has a length L = 5 [cm] and a charge Qrod = 85 [pc] uniformly distributed. The ring, located at a distance d = 23 [cm] from the origin, has a radius R = 8 [cm] and a charge Qring = 79 [pc] uniformly distributed. y [cm] R x [cm] 1. [2 Points] Calculate the magnitude of the electric field created by the rod at the origin. Erod [N/C] 2. [2 Points] What is the direction of the electric field vector created by the rod at the origin 3. [2 Points] Calculate the magnitude of the electric field created by the ring at the origin Ering [N/C] 4. [2 Points] What is the direction of the electric field vector created by the ring at the origin. 5. [2 Points] Calculate the linear charge density of the rod and select the corresponding unit. Arad =
R 0 x [cm] 1. [2 Points] Calculate the magnitude of the electric field created by the rod at the origin. Erod [N/C] 2. [2 Points] What is the direction of the electric field vector created by the rod at the origin 3. [2 Points] Calculate the magnitude of the electric field created by the ring at the origin. Ering [N/C] 4. [2 Points] What is the direction of the electric field vector created by the ring at the origin. y= 5. [2 Points] Calculate the linear charge density of the rod and select the corresponding unit. Ared= 6. [2 Points) Calculate the linear charge density of the ring. Aring = 7. [3 Points] The rod is moved upward so that the magnitude of the electric field of the rod is now 16.6 [N/C). Find the new distance y between the origin and the rod. [cm]
R to 1. [2 Points] Calculate the magnitude of the electric field created by the rod at the origin. Erod [N/C] 2. [2 Points] What is the direction of the electric field vector created by the rod at the origin • 3. [2 Po origin. E x [cm] 4.12 Po the oric Downward Upward To the right To the left electric field created by the ring at the ectric field vector created by the ring at 5. [2 Points] Calculate the linear charge density of the rod and select the corresponding unit. 6. [2 Points] Calculate the linear charge density of the ring. Aring= 7. [3 Points] The rod is moved upward so that the magnitude of the electric field of the rod is now 16.6 [N/C]. Find the new distance y between the origin and the rod. y= [cm]
1. [2 Points] Calculate the magnitude of the electric field created by the rod at the origin. Erod [N/C] 2. [2 Points] What is the direction of the electric field vector created by the rod at the origin 3. [2 Points] Calculate the magnitude of the electric field created by the ring at the origin Ering [N/C] 4. [2 Points] What is the direction of the electric field vector created by the ring at the origin 5. [2 Points] correspond R Om x [cm] To the left Downward Arad = 6. [2 Points Upward y= To the right of the rod and select the of the ring 7. [3 Points] The rod is moved upward so that the magnitude of the electric field of the rod is now 16.6 [N/C]. Find the new distance y between the origin and the rod [cm]
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