- What I Ve Filled In The Boxes Are What I Ve Got So Far And I Believe They Are Correct Need Help On The Empty Boxes Plea 1 (31.37 KiB) Viewed 11 times
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Using the force method, determine all member forces in the following two-fold statically indeterminate truss. Take a = 10 kN. b = 5 kN. c = 13 kN and EA the same for all the members. 3 m ●●● BO A 2 -2 m D с a 2 m. F b E * -2 m. G с
Part 1) Calculate the internal forces in the primary structure (by release member AC and DE). a) NAB 59.09 kN Your last answer was interpreted as follows: 59.09 kN b) NAC = 0 c) NAD -71.5 Your last answer was interpreted as follows: 0 kN d) NBD 59.88 e) NBC Your last answer was interpreted as follows: -71.5 kN Your last answer was interpreted as follows: 59.88 -37.37 kN Your last answer was interpreted as follows: -37.37 f) NCD 49.08 h) NCF g) NCE = -8.66 Your last answer was interpreted as follows: 49.08 kN Your last answer was interpreted as follows: -8.66 kN Your last answer was interpreted as follows: -21.63 kN -21.63 i) NDE = 0 Your last answer was interpreted as follows: 0 kN j) NDF = 20.55 kN k) NEF= 1) NEG = Your last answer was interpreted as follows: 20.55 -15.625 m) NFG = 8.593 kN kN Your last answer was interpreted as follows: -15.625 kN Your last answer was interpreted as follows: 8.593
Part 2) Calculate the internal forces in the first redundant structure by placing a unit load in the direction of AC). a) n¹ = 1.499 kN Your last answer was interpreted as follows: 1.499 kN b) nac c) n'AD f) nCD d) nBD = 1 e) nBC = -1.8 g) nCE Your last answer was interpreted as follows: 1 kN i) n'DE -1.802 Your last answer was interpreted as follows: -1.802 kN Your last answer was interpreted as follows: 1 kN k) nEF 1) NEG Your last answer was interpreted as follows: -1.8 kN 1.5 Your last answer was interpreted as follows: 1.5 kN h) ncp = 0 0 Your last answer was interpreted as follows: 0 kN Your last answer was interpreted as follows: 0 kN 0 j) nDF = 0 Your last answer was interpreted as follows: 0 kN Your last answer was interpreted as follows: 0 kN 0 Your last answer was interpreted as follows: 0 kN 0 Your last answer was interpreted as follows: 0 m) nFG 0 kN Your last answer was interpreted as follows: 0
Part 3) Calculate the internal forces in the second redundant structure by placing a unit load in the direction of DE. a) n², 0 kN AB b) n²AC c) n² AD e) n²Bc Your last answer was interpreted as follows: 0 g) n²cE d) n²D = 0 i) DE Your last answer was interpreted as follows: 0 0 0 Your last answer was interpreted as follows: 0 kN Your last answer was interpreted as follows: 0 kN f) ncp = -0.822 kN 0 Your last answer was interpreted as follows: 0 = -0.555 Your last answer was interpreted as follows: -0.822 h) nr = 1 kN kN Your last answer was interpreted as follows: -0.555 j) nr = -0.55 1) n²G = Your last answer was interpreted as follows: 1 1 kN Your last answer was interpreted as follows: 1 kN k) n²F = -0.832 m) n/FG = kN Your last answer was interpreted as follows: -0.55 kN Your last answer was interpreted as follows: -0.832 kN Your last answer was interpreted as follows: 0 kN kN Your last answer was interpreted as follows: 0
Part 4) Calculate the unknowns and calculate all the real internal forces. a) FAB = kN b) FAC kN kN c) FAD h) FCF i) FDE = d) FBD e) FBC = f) FCD g) FCE = || = m) FFG = = = j) FDF k) FEF = 1) FEG = = = kN kN kN kN kN kN kN kN kN kN