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For the given vectors V₁ and V₂, determine V₁ + V₂, V₁ + V2, V₁-V2, V₁ V2, V₁ V₂. Consider the vectors to be nondimensional. Assume V₁ = 12, V₂ = 19, a = 3, b= 5,0 = 22° V Answers: V₁ + V₂ = V₁ + V₂ = (i V₁-V₂= (i V₁xV₂ = (i V₁.V2= i+ i+ i+ i j+ j+ j+ i k) k) k)
Two uniform spheres are positioned as shown. Determine the gravitational force F which the titanium sphere exerts on the copper sphere. The value of R is 40 mm. R y 1 6.2 R Titanium Answer: F = (i 27° Copper 2.6 R x i+ j) (10-8) N
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