Figure 1 Show A Single Line Of An Electrical Power System Where T 1 Be 8 1 B 2 Line 1 T 2 Be T B 3 B 4 Load 2 Load 1 F 1 (44.25 KiB) Viewed 19 times
Figure 1 show a single line of an electrical power system, where: T-1 BE 8-1 B-2 Line-1 T-2 BE ť B-3 B-4 Load-2 Load-1 Figure 1. Single line diagram of an electric power system • Generator: 3-phase, Y-connection, 6.6 kV, 50Hz, R-0.001 2. L-4 mH • Transformer-1: 3-phase, Y-A connection. 6.6 kV:33 KV. equivalent impedance per-phase: Rp=0.01 2. Lph=2 mH, R=25 k2, L=45 H Line-1 per phase: R=0.0192+j45 92 • Transformer-2: 3-phase, A-Y connection, 33 kV:400V, equivalent impedance per-phase: Rp=0.01 52, Leh-2 mH, R=25k2, L=45 H • Load-1: 3-phase, Y-connection, impedance per-phase is 4+j7 2 • Load-2: 3-phase, Y-connection, 12 kW. PF-0.6 lagging. Assume that the output line-voltage on bus-4 V-40020 V determine 1) Total load current per-phase 2) Total load power and reactive power per-phase 3) Load power factor 4) Complete the table 1 5) Capacitor per-phase to improve the power factor up to 0.9 6) Total load current after adding the capacitor and completing the table 2
Table 1. Result of the bus-4 Vph (V) Iph (V) P3ph (W) Q3ph (VAR) PF Table 2.. Result of the bus-4 after using Power Capacitor Vph (V) Iph (V) P3ph (kW) Q3ph (kVAR) PF Bus-4 QC-ph(VAR) Cph(UF) Bus-4
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