THEORY ➤ Thevenin's Theorem: A two terminal network can be replaced by a voltage source with the value equal the open ci

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

THEORY ➤ Thevenin's Theorem: A two terminal network can be replaced by a voltage source with the value equal the open ci

Post by answerhappygod »

Theory Thevenin S Theorem A Two Terminal Network Can Be Replaced By A Voltage Source With The Value Equal The Open Ci 1
Theory Thevenin S Theorem A Two Terminal Network Can Be Replaced By A Voltage Source With The Value Equal The Open Ci 1 (52.97 KiB) Viewed 16 times
Theory Thevenin S Theorem A Two Terminal Network Can Be Replaced By A Voltage Source With The Value Equal The Open Ci 2
Theory Thevenin S Theorem A Two Terminal Network Can Be Replaced By A Voltage Source With The Value Equal The Open Ci 2 (23.31 KiB) Viewed 16 times
Theory Thevenin S Theorem A Two Terminal Network Can Be Replaced By A Voltage Source With The Value Equal The Open Ci 3
Theory Thevenin S Theorem A Two Terminal Network Can Be Replaced By A Voltage Source With The Value Equal The Open Ci 3 (41.68 KiB) Viewed 16 times
THEORY ➤ Thevenin's Theorem: A two terminal network can be replaced by a voltage source with the value equal the open circuit voltage across its terminals, in series with a resistor with the value equal to the equivalent resistance of the network. ▸ Norton's Theorem: A two terminal network can be replaced by a current source with the value equal to the short circuit current at its terminal, in parallel with a resistor with the value equal to the equivalent resistance of the network. The equivalent resistance of a two terminal network is equal to the open circuit voltage divided by the short circuit current. PROCEDURE: 1. Check the values of the resistors using the multimeter. Record the values in Table 1. 2. Connect the circuit of Figure 1. R47 10V 6.8 KQ R49 R₁ = 10 KO Prepared by Course Instructor: Maha Al-Sadoon R45 5.6 ΚΩ Figure 1 R51 20 KQ R43 5.1 ΚΩ 5V Pg. 3
ROCEDURE: . Check the values of the resistors using the multimeter. Record the values in Table 1. . Connect the circuit of Figure 1. R47 10V 6.8 Kn R49 A R₁ = 10 Kn B R45 5.6 ΚΩ Figure 1 R51> 20 KO R43 5.1 Kn 5V
3. Remove R₁ from the original circuit and measure the open circuit voltage Voc- 4. Measure the short circuit current Ise. This is accomplished by placing an Ammeter between A and B. In this manner, the Ammeter will act as a short circuit. 5. Replace the voltage sources with short circuits. With R, removed from the circuit, measure RT, using a multimeter. 6. Record the results in Table 2. REPORT: 1. Draw the Thevenin's and Norton's equivalent circuit obtained experimentally. 2. Compare step 1 with theoretical Thevenin and Norton's equivalent circuits obtained in prelab. Resistor R₁ Nominal value (Ohm) 6.8 kΩ Ohmmeter reading Theory Experiment % Error Thevenin's and Norton's Equivalent Circuits: Voc R₂ 10 kn Thevenin's Equivalent Circuit Table 4 Table 2 Resistor Values R3 5.6 k Isc R4 20 ΚΩ RT Norton's Equivalent Circuit Rs 5.1 k
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply