"+"=Wild-Type (Normal Function) | |- = Beta-Gal Mutation (Non-Functional) P- = Promoter Mutation (No Transcription) | Nd

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Wild Type Normal Function Beta Gal Mutation Non Functional P Promoter Mutation No Transcription Nd 1 (46.37 KiB) Viewed 9 times

"+"=Wild-Type (Normal Function) | |- = Beta-Gal Mutation (Non-Functional) P- = Promoter Mutation (No Transcription) | Nd Prokaryotic Operons - Bacteria (Disregard Attenuation) Z- = Repressor Mutation (Unable to Bind Operator = Repressor Mutation (Unable to Bind Allolactose Operator Mutation (Unable to Bind w/ Repressors) Wild-Type = 1* P*O* Z* (One Copy) Answer Types: *1 = Low Levels *II = High Levels * III = Both High/Low * IV = Neither High/Low A) Would cell transcription be functional if beta-galactosidase protein was present in the cell in low or high lactose levels? Both vs. none? Is P+ OcZ I P+ 0+Z+ B) For the same bacterium except it has an Is mutation instead of the I- mutation? In low glucose levels, is transcription of the lac operon taking place? C) Partial diploid with two copies of the lac operon, assuming glucose levels are low, would there be transcription in the cell in absence/presence of lactose? Is P+ OcZ I* P+ 0* Z* D) Non-mutated trp operon with a trpR gene mutation. Would there be transcription of trp operon in a high or low tryptophan environment? Both vs. none? (Essentially, respressors won't bind to tryptophan).