Prokaryotic Trp Operons - Bacteria (Disregard Attenuation) "+"=Wild-Type (Normal Function) | - = Beta-Gal Mutation (Non-

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answerhappygod
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Prokaryotic Trp Operons - Bacteria (Disregard Attenuation) "+"=Wild-Type (Normal Function) | - = Beta-Gal Mutation (Non-

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Prokaryotic Trp Operons Bacteria Disregard Attenuation Wild Type Normal Function Beta Gal Mutation Non 1
Prokaryotic Trp Operons Bacteria Disregard Attenuation Wild Type Normal Function Beta Gal Mutation Non 1 (26.44 KiB) Viewed 12 times
You just have to choose one of the answer types except for in question part "C" where you have to answer for both lactose and glucose levels. It either needs to be high levels, low levels, both high/low, or neither. Some of the information provided above is excess and not necessary.
Prokaryotic Trp Operons - Bacteria (Disregard Attenuation) "+"=Wild-Type (Normal Function) | - = Beta-Gal Mutation (Non-Functional ) | = Repressor Mutation (Unable to Bind Operator = Repressor Mutation (Unable to Bind Allolactose = Promoter Mutation (No Transcription) |0° = Operator Mutation (Unable to Bind w/ Repressors) Wild-Type = | P+ O+Z+(One Copy) Z- P- Q-II: Answer Types: *1 = Low Levels *II = High Levels * III = Both High/Low * IV = Neither High/Low A) A bacterium has a non-mutated copy of the lac operon and an I- mutation. Glucose levels are low; would transcription of the lac operon occur with high or low lactose levels? Both vs. none? B) For the same bacterium except it has an Is mutation instead of the I- mutation? In low glucose levels, is transcription of the lac operon taking place? C) Is the lac operon most fully transcribed in high/low lactose, as well as high/low glucose levels? (Answer must specify for the environment/levels of both lactose and glucose).
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