(d) Ca(HCO3)2 = 150 mg/L; Mg(HCO3)2 = 200 mg/L; CaSO4 = 180 mg/L; MgCl₂ = 95 mg/L; CaCl₂ = 137 mg/L; turbidity = 15 mg/L

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

(d) Ca(HCO3)2 = 150 mg/L; Mg(HCO3)2 = 200 mg/L; CaSO4 = 180 mg/L; MgCl₂ = 95 mg/L; CaCl₂ = 137 mg/L; turbidity = 15 mg/L

Post by answerhappygod »

D Ca Hco3 2 150 Mg L Mg Hco3 2 200 Mg L Caso4 180 Mg L Mgcl 95 Mg L Cacl 137 Mg L Turbidity 15 Mg L 1
D Ca Hco3 2 150 Mg L Mg Hco3 2 200 Mg L Caso4 180 Mg L Mgcl 95 Mg L Cacl 137 Mg L Turbidity 15 Mg L 1 (41.35 KiB) Viewed 11 times
please solve in 30 min.
(d) Ca(HCO3)2 = 150 mg/L; Mg(HCO3)2 = 200 mg/L; CaSO4 = 180 mg/L; MgCl₂ = 95 mg/L; CaCl₂ = 137 mg/L; turbidity = 15 mg/L; NaCl = 58.5 mg/L. Calculate: (i) Carbonate and non-carbonate hardness in degree Clark. (ii) The cost of lime- soda process, if lime (95% pure) is Rs.200/10 Kg and soda (86%pure) is Rs. 400/10 Kg for softening of 150,000 liters of hard water using Al2(SO4)3 as a coagulant @ 28.5 mg/L. (iii) A hard water sample having 530 ppm CaCO3 equivalent hardness was completely softened on passing over a zeolite bed. The exhausted bed was subsequently regenerated using 75 liters of 45 percent brine solution. Calculate the quantity of hard water that has been softened using zeolite softener.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply